What is the asymptotes of f(x)=(x^2+4)/(4x^2-4x-8) ?

The asymptotes of f(x)=(x^2+4)/(4x^2-4x-8) is Vertical: x=-1,x=2,Horizontal: y= 1/4

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asymptotes of f(x)=(x^2+4)/(4x^2-4x-8)

asymptotes

f (x) = \frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8}

Vertical : x = - 1, x = 2, Horizontal : y = \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} : x = - 1, x = 2

Horizontal Asymptotes of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} : y = \frac{1}{4}

Slant Asymptotes of

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8} :

None

Vertical : x = - 1, x = 2, Horizontal : y = \frac{1}{4}

(- 4, 0), (0, 9)

y + 7 = - 2 (x - 3)

f (x) = \frac{x - 9}{x ^{2} - 81}

x^{2} x + 1

y = lo g_{2} (x)

What is the asymptotes of f(x)=(x^2+4)/(4x^2-4x-8) ?
The asymptotes of f(x)=(x^2+4)/(4x^2-4x-8) is Vertical: x=-1,x=2,Horizontal: y= 1/4