What is the range of f(x)=x^2,-2<= x<= 5 ?

The range of f(x)=x^2,-2<= x<= 5 is 0<= f(x)<= 25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=x^2,-2<= x<= 5

range

f (x) = x^{2}, - 2 \leq x \leq 5

0 \leq f (x) \leq 25

Interval Notation

[0, 25]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2}, - 2 \leq x \leq 5 : - 2 \leq x \leq 5

Extreme Points of

x^{2}, - 2 \leq x \leq 5 :

Maximum

(- 2, 4),

Minimum

(0, 0),

Maximum

(5, 25)

Find the range for the interval

- 2 \leq x \leq 5 : 0 \leq f (x) \leq 25

Combine the ranges of all domain intervals to obtain the function range

0 \leq f (x) \leq 25

4 x^{2} - 4 x + 9

f (x) = - (5)^{x} + 5

(- \frac{1}{3}, \frac{1}{5}), (- \frac{11}{2}, \frac{9}{10})

f (x) = \frac{x - 3}{x ^{2} - 6 x + 9}

y = \frac{1}{2} x - 1

What is the range of f(x)=x^2,-2<= x<= 5 ?
The range of f(x)=x^2,-2<= x<= 5 is 0<= f(x)<= 25