What is the domain of f(x)=sqrt(-x^2+9x-8)-4 ?

The domain of f(x)=sqrt(-x^2+9x-8)-4 is 1<= x<= 8

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domain of f(x)=sqrt(-x^2+9x-8)-4

domain

f (x) = - x^{2} + 9 x - 8 - 4

1 \leq x \leq 8

Interval Notation

[1, 8]

Solution steps

Find non-negative values for radicals:

1 \leq x \leq 8

The function domain

1 \leq x \leq 8

f (x) = \frac{x + 4}{x - 2}

x^{4} + 4 x^{3} - 9

\frac{1}{x ^{3} + x - 2}

f (x) = 5 x + 11

\frac{- 6 x ^{2}}{( x - 8 ) ( x + 2 )}

What is the domain of f(x)=sqrt(-x^2+9x-8)-4 ?
The domain of f(x)=sqrt(-x^2+9x-8)-4 is 1<= x<= 8