What is the critical f(x)=2.6+1.4x-0.2x^2 ?

The critical f(x)=2.6+1.4x-0.2x^2 is x= 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=2.6+1.4x-0.2x^2

critical points

f (x) = 2.6 + 1.4 x - 0.2 x^{2}

x = \frac{7}{2}

Solution steps

2.6 + 1.4 x - 0.2 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{7}{2}

Identify critical points not in

f (x)

domain

Domain of

2.6 + 1.4 x - 0.2 x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{7}{2}

(3, - 1), (4, 7)

f (x) = 5 x^{2} + 5

\frac{x ^{2} - 1}{x - 1}

9 x + 7418 x + 38

x^{2} - 2 x - 8

What is the critical f(x)=2.6+1.4x-0.2x^2 ?
The critical f(x)=2.6+1.4x-0.2x^2 is x= 7/2