What is the inverse of f(x)=11x^2-8 ?

The inverse of f(x)=11x^2-8 is sqrt((x+8)/(11)),-sqrt((x+8)/(11))

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inverse of f(x)=11x^2-8

inverse

f (x) = 11 x^{2} - 8

\frac{x + 8}{11}, - \frac{x + 8}{11}

Solution steps

y = 11 x^{2} - 8

Replace

x

with

y

x = 11 y^{2} - 8

Solve for

y, x = 11 y^{2} - 8

\frac{x + 8}{11}, - \frac{x + 8}{11}

y = 2 x^{3} - 5

\frac{2}{x - 5}

f (x) = sin^{2} (x)

f (x) = - 7 x + 4

What is the inverse of f(x)=11x^2-8 ?
The inverse of f(x)=11x^2-8 is sqrt((x+8)/(11)),-sqrt((x+8)/(11))