What is the inverse of f(x)=(3x+1)/(1-7x) ?

The inverse of f(x)=(3x+1)/(1-7x) is -(1-x)/(3+7x)

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inverse of f(x)=(3x+1)/(1-7x)

inverse

f (x) = \frac{3 x + 1}{1 - 7 x}

- \frac{1 - x}{3 + 7 x}

Solution steps

y = \frac{3 x + 1}{1 - 7 x}

Replace

x

with

y

x = \frac{3 y + 1}{1 - 7 y}

Solve for

y, x = \frac{3 y + 1}{1 - 7 y}

- \frac{1 - x}{3 + 7 x}

x + 4

2 x^{3} + 5

x^{3} - 3 x^{2} - 72 x

f (x) = \frac{( x + 9 )}{x - 5}

\frac{2 x}{x - 3}

What is the inverse of f(x)=(3x+1)/(1-7x) ?
The inverse of f(x)=(3x+1)/(1-7x) is -(1-x)/(3+7x)