What is the domain of f(x)=((x^2-1))/(2x-3) ?

The domain of f(x)=((x^2-1))/(2x-3) is x 3/2

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domain of f(x)=((x^2-1))/(2x-3)

domain

f (x) = \frac{( x ^{2} - 1 )}{2 x - 3}

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}

The function domain

x < \frac{3}{2} or x > \frac{3}{2}

f (x) = \frac{x ^{2} + 3 x}{x ^{2} - x}

f (x) = - - \frac{10 x - 458}{49} - 3

f (x) = x e^{- 2 x}

\frac{1 + x}{1 + x ^{2}}

f (x) = - x - 7

What is the domain of f(x)=((x^2-1))/(2x-3) ?
The domain of f(x)=((x^2-1))/(2x-3) is x< 3/2 \lor x> 3/2