What is the inverse of (x^2-4)/(8x^2) ?

The inverse of (x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))

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inverse of (x^2-4)/(8x^2)

inverse

\frac{x ^{2} - 4}{8 x ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{8 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{8 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{8 y ^{2}}

- \frac{4}{8 x - 1}, - - \frac{4}{8 x - 1}

f (x) = \frac{1}{2} x^{4} + 2 x^{3}

2 cos (3 x - π)

y (θ) = \frac{θ + 3}{θ cos ( θ )}

f (x) = 2 (x - 3)^{3}

f (x) = \frac{x - 9}{x - 2}

What is the inverse of (x^2-4)/(8x^2) ?
The inverse of (x^2-4)/(8x^2) is sqrt(-4/(8x-1)),-sqrt(-4/(8x-1))