What is the domain of f(x)=((x^2+3))/(x(5x-1)) ?

The domain of f(x)=((x^2+3))/(x(5x-1)) is x 1/5

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domain of f(x)=((x^2+3))/(x(5x-1))

domain

f (x) = \frac{( x ^{2} + 3 )}{x ( 5 x - 1 )}

x < 0 or 0 < x < \frac{1}{5} or x > \frac{1}{5}

Interval Notation

(- \infty, 0) \cup (0, \frac{1}{5}) \cup (\frac{1}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = \frac{1}{5}

The function domain

x < 0 or 0 < x < \frac{1}{5} or x > \frac{1}{5}

- 3 tan (3 π x)

f (x) = - 1 + x

f (x) = \frac{2 x + 7}{3 x - 7}

f (x) = 2 x - 9

- 2 x + 2 y = - 4

What is the domain of f(x)=((x^2+3))/(x(5x-1)) ?
The domain of f(x)=((x^2+3))/(x(5x-1)) is x<0\lor 0<x< 1/5 \lor x> 1/5