What is the domain of f(x)=(-3x^2+8x)/(3x+4) ?

The domain of f(x)=(-3x^2+8x)/(3x+4) is x -4/3

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domain of f(x)=(-3x^2+8x)/(3x+4)

domain

f (x) = \frac{- 3 x ^{2} + 8 x}{3 x + 4}

x < - \frac{4}{3} or x > - \frac{4}{3}

Interval Notation

(- \infty, - \frac{4}{3}) \cup (- \frac{4}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{4}{3}

The function domain

x < - \frac{4}{3} or x > - \frac{4}{3}

15 x^{\frac{2}{3}} - 10 x

f (x) = x^{2} + 2 x

f (x) = \frac{1}{16 - x ^{2}}

f (x) = \frac{6}{( x - 5 ) ^{3}}

f (x) = \frac{x + 6}{x - 7}

What is the domain of f(x)=(-3x^2+8x)/(3x+4) ?
The domain of f(x)=(-3x^2+8x)/(3x+4) is x<-4/3 \lor x>-4/3