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perpendicular-1/5perpendicular inverse of f(x)=sqrt(2x)-8inverse domain of (7x-21)/((x-7)(x+1))domain intercepts of 1/(x^2)intercepts domain of (3x)/(2-x)domain
Frequently Asked Questions (FAQ)
What is the inverse of f(x)=\sqrt[3]{x^2-8} ?
The inverse of f(x)=\sqrt[3]{x^2-8} is sqrt(x^3+8),-sqrt(x^3+8)