What is the midpoint ((2pi)/3 ,0),((2pi)/6 ,0) ?

The midpoint ((2pi)/3 ,0),((2pi)/6 ,0) is (pi/2 ,0)

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midpoint ((2pi)/3 ,0),((2pi)/6 ,0)

midpoint

(\frac{2 π}{3}, 0), (\frac{2 π}{6}, 0)

(\frac{π}{2}, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (\frac{2 π}{3}, 0), (x_{2}, y_{2}) = (\frac{2 π}{6}, 0)

= (\frac{\frac{2 π}{6} + \frac{2 π}{3}}{2}, \frac{0 + 0}{2})

Refine

= (\frac{π}{2}, 0)

y + 1 = \frac{4}{3} x

4 x + 7 y = 8, (4, - 2)

(- 1.5) (0.6)

f (x) = \frac{x ^{2} + x - 6}{x ^{2} - 4}

f (x) = \frac{x ^{2} - 2 x + 1}{x ^{2} + x - 2}

What is the midpoint ((2pi)/3 ,0),((2pi)/6 ,0) ?
The midpoint ((2pi)/3 ,0),((2pi)/6 ,0) is (pi/2 ,0)