What is the inverse of f(x)=(2x-1)/(2x+9) ?

The inverse of f(x)=(2x-1)/(2x+9) is (-1-9x)/(2(-1+x))

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inverse of f(x)=(2x-1)/(2x+9)

inverse

f (x) = \frac{2 x - 1}{2 x + 9}

\frac{- 1 - 9 x}{2 ( - 1 + x )}

Solution steps

y = \frac{2 x - 1}{2 x + 9}

Replace

x

with

y

x = \frac{2 y - 1}{2 y + 9}

Solve for

y, x = \frac{2 y - 1}{2 y + 9}

\frac{- 1 - 9 x}{2 ( - 1 + x )}

f (x) = \frac{x + 7}{x ^{2} + 2 x - 3}

f (x) = \frac{3 - x ^{2}}{x ^{2} - 4}

2 y = - 7

f (x) = - \frac{x ^{3}}{x ^{2} - 3}

(x - 3) x

What is the inverse of f(x)=(2x-1)/(2x+9) ?
The inverse of f(x)=(2x-1)/(2x+9) is (-1-9x)/(2(-1+x))