What is the domain of f(x)=((9x-6))/(sqrt(x+9)) ?

The domain of f(x)=((9x-6))/(sqrt(x+9)) is x>-9

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domain of f(x)=((9x-6))/(sqrt(x+9))

domain

f (x) = \frac{( 9 x - 6 )}{x + 9}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

5 x - 6 y + 30 = 0

f (x) = x + 4 + 2

8 x^{3} - 24 x + 12

\frac{x ^{2} - 9}{x - 3}

y = \frac{( x + 1 )}{4}

What is the domain of f(x)=((9x-6))/(sqrt(x+9)) ?
The domain of f(x)=((9x-6))/(sqrt(x+9)) is x>-9