What is the inverse of f(x)= 1/(x^2)+4 ?

The inverse of f(x)= 1/(x^2)+4 is sqrt(1/(x-4)),-sqrt(1/(x-4))

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inverse of f(x)= 1/(x^2)+4

inverse

f (x) = \frac{1}{x ^{2}} + 4

\frac{1}{x - 4}, - \frac{1}{x - 4}

Solution steps

y = \frac{1}{x ^{2}} + 4

Replace

x

with

y

x = \frac{1}{y ^{2}} + 4

Solve for

y, x = \frac{1}{y ^{2}} + 4

\frac{1}{x - 4}, - \frac{1}{x - 4}

f (x) = tan (\frac{x}{8 x ^{2} + 3})

f (x) = 9 x + 12

6 x - 2 y = 8

f (x) = 2 x - 3 x^{\frac{2}{3}}

(4, 2), (1, - 3)

What is the inverse of f(x)= 1/(x^2)+4 ?
The inverse of f(x)= 1/(x^2)+4 is sqrt(1/(x-4)),-sqrt(1/(x-4))