What is the domain of f(x)= 1/(x^4-1) ?

The domain of f(x)= 1/(x^4-1) is x 1

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domain of f(x)= 1/(x^4-1)

domain

f (x) = \frac{1}{x ^{4} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

cot (x)

f (x) = \frac{1}{x + 4} + 2

f (x) = \frac{x ^{2} - 4 x + 6}{x + 4}

h (x) = \frac{5}{2} x + 4

f (x) = \frac{1}{x + 5}

What is the domain of f(x)= 1/(x^4-1) ?
The domain of f(x)= 1/(x^4-1) is x<-1\lor-1<x<1\lor x>1