What is the shift f(x)=sin(2(x-pi/2)) ?

The shift f(x)=sin(2(x-pi/2)) is Phase: pi/2 , Vertical:0

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shift f(x)=sin(2(x-pi/2))

shift

f (x) = sin (2 (x - \frac{π}{2}))

Phase : \frac{π}{2}, Vertical : 0

Solution steps

Simplify

sin (2 (x - \frac{π}{2})) : sin (2 x - π)

f (x) = sin (2 x - π)

g (B x - C) = sin (2 x - π), B = 2, C = π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{π}{2}

\frac{π}{2}

The vertical shift

D

0

0

y = - x - 2

\frac{cos ( x )}{1 + sin ( x )}

f (x) = e^{x} - 1

0.2 (x + 3)^{2} (x - 3)^{3}

(9, - 6), (- 1, 2)

What is the shift f(x)=sin(2(x-pi/2)) ?
The shift f(x)=sin(2(x-pi/2)) is Phase: pi/2 , Vertical:0