What is the range of 26sin(0.5x-2)+68 ?

The range of 26sin(0.5x-2)+68 is 42<= f(x)<= 94

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range of 26sin(0.5x-2)+68

range

26 sin (0.5 x - 2) + 68

42 \leq f (x) \leq 94

Interval Notation

[42, 94]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (0.5 x - 2) \leq 1

- 1 \leq sin (0.5 x - 2) \leq 1

Multiply the edges of the range by:

26

- 26 \leq 26 sin (0.5 x - 2) \leq 26

Add to the edges of the range:

68

42 \leq 26 sin (0.5 x - 2) + 68 \leq 94

Therefore the range is

42 \leq f (x) \leq 94

f (x) = 17

f (x) = \frac{4 x - 3}{6 - 3 x}

cos (x + \frac{π}{2})

f (x) = \frac{x ^{2} - 5 x - 6}{x ^{2} - 2 x - 3}

f (x) = (\frac{8}{x}) (x + 3)

What is the range of 26sin(0.5x-2)+68 ?
The range of 26sin(0.5x-2)+68 is 42<= f(x)<= 94