What is the critical (2x)/(5(x^2)^{4/5)} ?

The critical (2x)/(5(x^2)^{4/5)} is None

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critical (2x)/(5(x^2)^{4/5)}

critical points

\frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}}

None

Solution steps

\frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}} : x < 0 or x > 0

\frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}}

is not defined at

x = 0

, therefore:

None

f (x) = \frac{1}{5 + e ^{3 x}}

\frac{6 x + 7}{5 x - 6}

X + ln (X^{2} - 1)

y = lo g_{3} (4 x + 18) - 3

m = - 4, (7, 8)

What is the critical (2x)/(5(x^2)^{4/5)} ?
The critical (2x)/(5(x^2)^{4/5)} is None