What is the range of f(x)=(4x^2-1)/(2x-1) ?

The range of f(x)=(4x^2-1)/(2x-1) is f(x) 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=(4x^2-1)/(2x-1)

range

f (x) = \frac{4 x ^{2} - 1}{2 x - 1}

f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{4 x ^{2} - 1}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

Simplify

\frac{4 x ^{2} - 1}{2 x - 1} : 2 x + 1

Extreme Points of

2 x + 1 :

None

Find the range for the interval

- \infty < x < \frac{1}{2} : - \infty < f (x) < 2

Find the range for the interval

\frac{1}{2} < x < \infty : 2 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) < 2 or f (x) > 2

f (x) < 2 or f (x) > 2

y = \frac{1}{3} x - 2, (3, - 3)

3 y = - 9 x + 15

f (x) = (x - 3)^{3}

f (x) = x + 14

f (x) = 2 x - 8 x

What is the range of f(x)=(4x^2-1)/(2x-1) ?
The range of f(x)=(4x^2-1)/(2x-1) is f(x)<2\lor f(x)>2