What is the perpendicular y= 1/3 x-2,(3,-3) ?

The perpendicular y= 1/3 x-2,(3,-3) is y=-3x+6

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perpendicular y= 1/3 x-2,(3,-3)

perpendicular

y = \frac{1}{3} x - 2, (3, - 3)

y = - 3 x + 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{3} x - 2

that passes through

(3, - 3)

Find the slope of

y = \frac{1}{3} x - 2 : m = \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = - 3

Find the line with slope m=

- 3

and passing through

(3, - 3) : y = - 3 x + 6

y = - 3 x + 6

3 y = - 9 x + 15

f (x) = (x - 3)^{3}

f (x) = x + 14

f (x) = 2 x - 8 x

\frac{1}{x ^{3}}

What is the perpendicular y= 1/3 x-2,(3,-3) ?
The perpendicular y= 1/3 x-2,(3,-3) is y=-3x+6