What is the domain of x^2-8,x>= 0 ?

The domain of x^2-8,x>= 0 is x>= 0

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domain of x^2-8,x>= 0

domain

x^{2} - 8, x \geq 0

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Set the domain to the given interval

x \geq 0

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq 0

f (x) = - 16 t^{2} + 32 t + 2

f (x) = x^{3} - 2 x^{2} - 23 x - 6

(- 3, 4), (2, - 9)

(8.2) (2.5)

f (x) = 7 x - 1