What is the domain of f(x)= 1/(x^2+x+3) ?

The domain of f(x)= 1/(x^2+x+3) is -infinity <x<infinity

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domain of f(x)= 1/(x^2+x+3)

domain

f (x) = \frac{1}{x ^{2} + x + 3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - 11 - x

y = \frac{1}{400} x^{2} - x + 150

g (x) = \frac{x + 5}{x ^{2} - 36}

- \frac{1}{x - 3} - 1

\frac{x - 3}{x + 3}

What is the domain of f(x)= 1/(x^2+x+3) ?
The domain of f(x)= 1/(x^2+x+3) is -infinity <x<infinity