What is the inverse of f(x)=((x-9))/((x+9)) ?

The inverse of f(x)=((x-9))/((x+9)) is (-9-9x)/(x-1)

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inverse of f(x)=((x-9))/((x+9))

inverse

f (x) = \frac{( x - 9 )}{( x + 9 )}

\frac{- 9 - 9 x}{x - 1}

Solution steps

y = \frac{x - 9}{x + 9}

Replace

x

with

y

x = \frac{y - 9}{y + 9}

Solve for

y, x = \frac{y - 9}{y + 9}

\frac{- 9 - 9 x}{x - 1}

2 x - y = 5

f (x) = \frac{x + 1}{x ^{2} - 4 x - 12}

(\frac{3}{2}, - 2), (\frac{- 1}{2}, 0)

- 2 cos (4 π x)

f (x) = 2

What is the inverse of f(x)=((x-9))/((x+9)) ?
The inverse of f(x)=((x-9))/((x+9)) is (-9-9x)/(x-1)