What is the inverse of f(x)=((7x+1))/(x-3) ?

The inverse of f(x)=((7x+1))/(x-3) is (1+3x)/(x-7)

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inverse of f(x)=((7x+1))/(x-3)

inverse

f (x) = \frac{( 7 x + 1 )}{x - 3}

\frac{1 + 3 x}{x - 7}

Solution steps

y = \frac{7 x + 1}{x - 3}

Replace

x

with

y

x = \frac{7 y + 1}{y - 3}

Solve for

y, x = \frac{7 y + 1}{y - 3}

\frac{1 + 3 x}{x - 7}

y = - \frac{4}{5} x + 4

f (x) = \frac{( \frac{x}{5} )}{( \frac{x}{5} ) + 5}

3 x

f (x) = - 2 x^{2} + 5 x - 6

y = 12 x - 20

What is the inverse of f(x)=((7x+1))/(x-3) ?
The inverse of f(x)=((7x+1))/(x-3) is (1+3x)/(x-7)