What is the domain of f(x)=sqrt(-x^2+12x-27) ?

The domain of f(x)=sqrt(-x^2+12x-27) is 3<= x<= 9

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domain of f(x)=sqrt(-x^2+12x-27)

domain

f (x) = - x^{2} + 12 x - 27

3 \leq x \leq 9

Interval Notation

[3, 9]

Solution steps

Find non-negative values for radicals:

3 \leq x \leq 9

The function domain

3 \leq x \leq 9

(- 4, 8), (1, 7.5)

\frac{10 x ^{2} + 8 x}{x}

y = 6 x - 4

f (x) = \frac{5}{9} (x - 32)

f (x) = - 11 cot (\frac{1}{5} x)

What is the domain of f(x)=sqrt(-x^2+12x-27) ?
The domain of f(x)=sqrt(-x^2+12x-27) is 3<= x<= 9