What is the extreme f(x)=x^8e^x-2 ?

The extreme f(x)=x^8e^x-2 is Maximum(-8,(16777216)/(e^8)-2),Minimum(0,-2)

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extreme f(x)=x^8e^x-2

extreme points

f (x) = x^{8} e^{x} - 2

Maximum (- 8, \frac{16777216}{e ^{8}} - 2), Minimum (0, - 2)

Solution steps

f^{'} (x) = e^{x} x^{8} + 8 e^{x} x^{7}

Find intervals:

Increasing

: - \infty < x < - 8,

Decreasing

: - 8 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 8

into

x^{8} e^{x} - 2 : \frac{16777216}{e ^{8}} - 2

Maximum (- 8, \frac{16777216}{e ^{8}} - 2)

Plug

x = 0

into

x^{8} e^{x} - 2 : - 2

Minimum (0, - 2)

Maximum (- 8, \frac{16777216}{e ^{8}} - 2), Minimum (0, - 2)

\frac{2}{x ^{2} - 9}

y = 8 x + 7

f (x) = x^{4} + y^{2} - x y = 81

f (x) = - (x + 9)^{2} + 5

(0.8, 0.3), (1.4, 2.1)

What is the extreme f(x)=x^8e^x-2 ?
The extreme f(x)=x^8e^x-2 is Maximum(-8,(16777216)/(e^8)-2),Minimum(0,-2)