What is the inverse of f(x)=(2x-3)^2+1 ?

The inverse of f(x)=(2x-3)^2+1 is (sqrt(x-1)+3)/2 ,(-sqrt(x-1)+3)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(2x-3)^2+1

inverse

f (x) = (2 x - 3)^{2} + 1

\frac{x - 1 + 3}{2}, \frac{- x - 1 + 3}{2}

Solution steps

y = (2 x - 3)^{2} + 1

Replace

x

with

y

x = (2 y - 3)^{2} + 1

Solve for

y, x = (2 y - 3)^{2} + 1

\frac{x - 1 + 3}{2}, \frac{- x - 1 + 3}{2}

(3, 6), (5.5, 5)

y = \frac{x ^{3}}{3} - 2 x^{2} - 12 x

(0, 2), (1, 4)

g (x) = x^{2} + 3

f (x) = \frac{1}{( x - 2 )}

What is the inverse of f(x)=(2x-3)^2+1 ?
The inverse of f(x)=(2x-3)^2+1 is (sqrt(x-1)+3)/2 ,(-sqrt(x-1)+3)/2