What is the domain of f(x)=(sqrt(x+2))/(x^2+4) ?

The domain of f(x)=(sqrt(x+2))/(x^2+4) is x>=-2

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domain of f(x)=(sqrt(x+2))/(x^2+4)

domain

f (x) = \frac{x + 2}{x ^{2} + 4}

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

f (x) = \frac{x + 3}{x - 1}

\frac{x + 3}{x - 1}

f (x) = \frac{x ^{4}}{x ^{2} + x - 6}

(6, - 2), (- 4, 4)

(8, 10), (12, - 6)

What is the domain of f(x)=(sqrt(x+2))/(x^2+4) ?
The domain of f(x)=(sqrt(x+2))/(x^2+4) is x>=-2