What is the domain of f(x)= 2/(sqrt(2x-5)) ?

The domain of f(x)= 2/(sqrt(2x-5)) is x> 5/2

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domain of f(x)= 2/(sqrt(2x-5))

domain

f (x) = \frac{2}{2 x - 5}

x > \frac{5}{2}

Interval Notation

(\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{2}

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

x > \frac{5}{2}

f (x) = - 3 x - 2

f (x) = 100 - 4 x^{2}

f (x) = x^{(\frac{1}{3})}

f (x) = \frac{x + 5}{x - 6}

f (x) = - x^{\frac{2}{3}} (x - 2)

What is the domain of f(x)= 2/(sqrt(2x-5)) ?
The domain of f(x)= 2/(sqrt(2x-5)) is x> 5/2