What is the critical 1/3 x^3+2x^2-5x+8/3 ?

The critical 1/3 x^3+2x^2-5x+8/3 is x=-5,x=1

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critical 1/3 x^3+2x^2-5x+8/3

critical points

\frac{1}{3} x^{3} + 2 x^{2} - 5 x + \frac{8}{3}

x = - 5, x = 1

Solution steps

\frac{1}{3} x^{3} + 2 x^{2} - 5 x + \frac{8}{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{3} x^{3} + 2 x^{2} - 5 x + \frac{8}{3} : - \infty < x < \infty

All critical points are in domain

x = - 5, x = 1

f (x) = (2 x + 3)^{4} (x - 3)^{5}

(2, - 73), (62, - 33)

- 3 x - 2

\frac{8}{( 2 x - 5 ) ^{3}}

f (x) = - 2 (3^{x + 1}) + 2

What is the critical 1/3 x^3+2x^2-5x+8/3 ?
The critical 1/3 x^3+2x^2-5x+8/3 is x=-5,x=1