What is the domain of ((x+3))/((x^2-9)) ?

The domain of ((x+3))/((x^2-9)) is x 3

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domain of ((x+3))/((x^2-9))

domain

\frac{( x + 3 )}{( x ^{2} - 9 )}

x < - 3 or - 3 < x < 3 or x > 3

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = 2 x - 8

(8, - 9), (0, 5)

f (x) = 5 cos (4 x)

g (x) = 2 x - 3

y = 8 x - 3 - \frac{8 π}{3}

What is the domain of ((x+3))/((x^2-9)) ?
The domain of ((x+3))/((x^2-9)) is x<-3\lor-3<x<3\lor x>3