What is the intercepts of f(x)=(x+1)^2-1 ?

The intercepts of f(x)=(x+1)^2-1 is X Intercepts: (0,0),(-2,0),Y Intercepts: (0,0)

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intercepts of f(x)=(x+1)^2-1

intercepts

f (x) = (x + 1)^{2} - 1

X Intercepts : (0, 0), (- 2, 0), Y Intercepts : (0, 0)

Solution steps

x -

axis interception points of

(x + 1)^{2} - 1 : (0, 0), (- 2, 0)

y -

axis interception point of

(x + 1)^{2} - 1 : (0, 0)

X Intercepts : (0, 0), (- 2, 0), Y Intercepts : (0, 0)

x^{2} + 3

f (x) = x^{2} + 5 x + 6

f (x) = 1.1011 E 13

f (x) = \frac{4}{x + 2} + x

(6, 3), (- 1, - 5)

What is the intercepts of f(x)=(x+1)^2-1 ?
The intercepts of f(x)=(x+1)^2-1 is X Intercepts: (0,0),(-2,0),Y Intercepts: (0,0)