What is the inverse of f(x)=x^2+2x-3,x<=-1 ?

The inverse of f(x)=x^2+2x-3,x<=-1 is -1+sqrt(x+4),-sqrt(x+4)-1

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inverse of f(x)=x^2+2x-3,x<=-1

inverse

f (x) = x^{2} + 2 x - 3, x \leq - 1

- 1 + x + 4, - x + 4 - 1

Solution steps

y = x^{2} + 2 x - 3

Replace

x

with

y

x = y^{2} + 2 y - 3

Solve for

y, x = y^{2} + 2 y - 3

- 1 + x + 4, - x + 4 - 1

(- 3, 5), (7, - 9)

y = 2 x^{2} + 12 x - 2

f (x) = \frac{4 x}{9 + x}

(1.1) (6.13)

(- 3, - 4), (4, 6)

What is the inverse of f(x)=x^2+2x-3,x<=-1 ?
The inverse of f(x)=x^2+2x-3,x<=-1 is -1+sqrt(x+4),-sqrt(x+4)-1