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Popular >

range of 16-(20x+15)^2

Solution

range

16 - (20 x + 15)^{2}

Solution

f (x) \leq 16

+1

Interval Notation

(- \infty, 16]

Solution steps

Vertex of

16 - (20 x + 15)^{2} :

Maximum

(- \frac{3}{4}, 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 400,

Vertex

(x_{v}, y_{v}) = (- \frac{3}{4}, 16)

f (x) \leq 16

Popular Examples

intercepts of (x^2)/(x-1)intercepts

\frac{x ^{2}}{x - 1}

inverse of h(x)=5(x-9)inverse

h (x) = 5 (x - 9)

range of x/(2x^2+4)range

\frac{x}{2 x ^{2} + 4}

inverse of f(x)=3sqrt(x)inverse

f (x) = 3 x

domain of x^2-6x+7 domain

x^{2} - 6 x + 7

Frequently Asked Questions (FAQ)

What is the range of 16-(20x+15)^2 ?
The range of 16-(20x+15)^2 is f(x)<= 16