What is the extreme f(x)=0.05x+20+(125)/x ?

The extreme f(x)=0.05x+20+(125)/x is Maximum(-50,15),Minimum(50,25)

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extreme f(x)=0.05x+20+(125)/x

extreme points

f (x) = 0.05 x + 20 + \frac{125}{x}

Maximum (- 50, 15), Minimum (50, 25)

Solution steps

Find the critical points:

x = - 50, x = 50

Domain of

0.05 x + 20 + \frac{125}{x} : x < 0 or x > 0

Find intervals:

Increasing

: - \infty < x < - 50,

Decreasing

: - 50 < x < 0,

Decreasing

: 0 < x < 50,

Increasing

: 50 < x < \infty

Plug the extreme point

x = - 50

into

0.05 x + 20 + \frac{125}{x} \Rightarrow y = 15

Maximum (- 50, 15)

Plug the extreme point

x = 50

into

0.05 x + 20 + \frac{125}{x} \Rightarrow y = 25

Minimum (50, 25)

Maximum (- 50, 15), Minimum (50, 25)

4 x - y = - 1

4 x - 7 = - 3

g (x) = 9 x - 13

f (x) = \frac{1}{x + 3}

y = 3 + x

What is the extreme f(x)=0.05x+20+(125)/x ?
The extreme f(x)=0.05x+20+(125)/x is Maximum(-50,15),Minimum(50,25)