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Popular >

range of f(x)=x^2-8x+15

Solution

range

f (x) = x^{2} - 8 x + 15

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} - 8 x + 15 :

Minimum

(4, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (4, - 1)

f (x) \geq - 1

Popular Examples

range of y=(2x+3)/(4x+1)range

y = \frac{2 x + 3}{4 x + 1}

line (6,5),(3,5)line

(6, 5), (3, 5)

extreme y=(x^2+1)/(x+1)extreme points

y = \frac{x ^{2} + 1}{x + 1}

domain of f(x)=(x^2)/(x+2)domain

f (x) = \frac{x ^{2}}{x + 2}

extreme y=sqrt(2x-x^2)extreme points

y = 2 x - x^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-8x+15 ?
The range of f(x)=x^2-8x+15 is f(x)>=-1