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Popular >

distance (6,5),(2,0)

Solution

distance

(6, 5), (2, 0)

Solution

41

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(6, 5)

and

(2, 0)

is

= (2 - 6)^{2} + (0 - 5)^{2}

Simplify

= 41

Popular Examples

extreme f(x)=2x^4-8x^3 extreme points

f (x) = 2 x^{4} - 8 x^{3}

critical f(x)=-5x^2+40x critical points

f (x) = - 5 x^{2} + 40 x

intercepts of y=x^2-x-42 intercepts

y = x^{2} - x - 42

domain of f(x)=-1/3 sqrt(x)domain

f (x) = - \frac{1}{3} x

parallel 2x-3y=9,(2,-1)parallel

2 x - 3 y = 9, (2, - 1)

Frequently Asked Questions (FAQ)

What is the distance (6,5),(2,0) ?
The distance (6,5),(2,0) is square root of 41