What is the monotone f(x)=-4x^2+6x+1 ?

The monotone f(x)=-4x^2+6x+1 is Increasing:-infinity <x< 3/4 ,Decreasing: 3/4 <x<infinity

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monotone f(x)=-4x^2+6x+1

monotone intervals

f (x) = - 4 x^{2} + 6 x + 1

Increasing : - \infty < x < \frac{3}{4}, Decreasing : \frac{3}{4} < x < \infty

Solution steps

f^{'} (x) = - 8 x + 6

Find intervals:

Increasing

: - \infty < x < \frac{3}{4},

Decreasing

: \frac{3}{4} < x < \infty

Increasing : - \infty < x < \frac{3}{4}, Decreasing : \frac{3}{4} < x < \infty

f (x) = x^{3} e^{x}

sin (2 x)

3 x - 4 y = - 12

(7, 1), (16, - 12)

\frac{x ^{3}}{x ^{2} - 4}

What is the monotone f(x)=-4x^2+6x+1 ?
The monotone f(x)=-4x^2+6x+1 is Increasing:-infinity <x< 3/4 ,Decreasing: 3/4 <x<infinity