What is the inverse of f(x)=(x^2-4)/(4x^2) ?

The inverse of f(x)=(x^2-4)/(4x^2) is sqrt(-4/(4x-1)),-sqrt(-4/(4x-1))

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inverse of f(x)=(x^2-4)/(4x^2)

inverse

f (x) = \frac{x ^{2} - 4}{4 x ^{2}}

- \frac{4}{4 x - 1}, - - \frac{4}{4 x - 1}

Solution steps

y = \frac{x ^{2} - 4}{4 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 4}{4 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 4}{4 y ^{2}}

- \frac{4}{4 x - 1}, - - \frac{4}{4 x - 1}

f (x) = 4 - 2 sin (3 x - π)

y = 4 0^{- (x + 5.5)} + 2.35

f (x) = \frac{x - 3}{x ^{2} + 4}

y = - \frac{1}{3} x^{2} + 4 x + 11

x^{2} + 6 x + 6

What is the inverse of f(x)=(x^2-4)/(4x^2) ?
The inverse of f(x)=(x^2-4)/(4x^2) is sqrt(-4/(4x-1)),-sqrt(-4/(4x-1))