What is the domain of (x^2-9)/(x^2-4x+3) ?

The domain of (x^2-9)/(x^2-4x+3) is x 3

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domain of (x^2-9)/(x^2-4x+3)

domain

\frac{x ^{2} - 9}{x ^{2} - 4 x + 3}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = \frac{- 2 x + 4}{x ^{2} - 4}

f (x) = 5 \cdot 2^{x}

f (x) = \frac{4 x + 9}{3 x - 4}

f (x) = - \frac{1}{2} x^{2} + 4 x - 2

What is the domain of (x^2-9)/(x^2-4x+3) ?
The domain of (x^2-9)/(x^2-4x+3) is x<1\lor 1<x<3\lor x>3