What is the perpendicular 3x+4y=7 ?

The perpendicular 3x+4y=7 is y= 4/3 x+b

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perpendicular 3x+4y=7

perpendicular

3 x + 4 y = 7

y = \frac{4}{3} x + b

Solution steps

Find the slope of

3 x + 4 y = 7 : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Line with slope m=

\frac{4}{3} : y = \frac{4}{3} x + b

y = \frac{4}{3} x + b

f (x) = x^{2} - 8 x + 12

(- 5, - 5), (3, - 4)

f (x) = 8 x

f (x) = 4 - 4 x

\frac{x + 4}{x ^{2} - 9}