What is the domain of f(x)=\sqrt[4]{2x^2-6} ?

The domain of f(x)=\sqrt[4]{2x^2-6} is x = sqrt(3)

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domain of f(x)=\sqrt[4]{2x^2-6}

domain

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = 5 + x + 8

\frac{6}{6 - x}

f (x) = \frac{4 x ^{2} + 5}{6 x + 4}

f (x) = \frac{x ^{4}}{x ^{2} + x - 12}

f (x) = x^{6} - 2 x^{3} + 1

What is the domain of f(x)=\sqrt[4]{2x^2-6} ?
The domain of f(x)=\sqrt[4]{2x^2-6} is x<=-sqrt(3)\lor x>= sqrt(3)