What is the inverse of f(x)=\sqrt[3]{x+2}+2 ?

The inverse of f(x)=\sqrt[3]{x+2}+2 is x^3-6x^2+12x-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{x+2}+2

inverse

x^{3} - 6 x^{2} + 12 x - 10

Solution steps

Replace

x

with

y

Solve for

x^{3} - 6 x^{2} + 12 x - 10

16 - x^{2}

f (x) = \frac{( x - 5 )}{4}

f (x) = (x - 2)^{2} + 3

f (x) = \frac{x ^{2} + 3}{5 x - 2 x ^{2}}

f (x) = \frac{2 x - 5}{x ^{2} - 5 x + 6}

What is the inverse of f(x)=\sqrt[3]{x+2}+2 ?
The inverse of f(x)=\sqrt[3]{x+2}+2 is x^3-6x^2+12x-10