What is the domain of f(x)=sqrt(2/(x-1)) ?

The domain of f(x)=sqrt(2/(x-1)) is x>1

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domain of f(x)=sqrt(2/(x-1))

domain

f (x) = \frac{2}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = \frac{x + 5}{x ^{2} - 16}

f (x) = e

f (x) = \frac{x + 3}{x - 5}

f (x) = \frac{3}{x ^{2} - 2 x - 15}

\frac{1}{x}

What is the domain of f(x)=sqrt(2/(x-1)) ?
The domain of f(x)=sqrt(2/(x-1)) is x>1