What is the domain of ((x-3))/(x^2-4x-12) ?

The domain of ((x-3))/(x^2-4x-12) is x 6

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domain of ((x-3))/(x^2-4x-12)

domain

\frac{( x - 3 )}{x ^{2} - 4 x - 12}

x < - 2 or - 2 < x < 6 or x > 6

Interval Notation

(- \infty, - 2) \cup (- 2, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 2

The function domain

x < - 2 or - 2 < x < 6 or x > 6

f (x) = x - 8

9 x^{5}

(9, - 9), (- 5, - 10)

f (x) = 3 x^{4} - 2 x^{2} + 6

y = - \frac{1}{2} x - 4, (3, 3)

What is the domain of ((x-3))/(x^2-4x-12) ?
The domain of ((x-3))/(x^2-4x-12) is x<-2\lor-2<x<6\lor x>6