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Popular >

distance (2,-1),(8,-1)

Solution

distance

(2, - 1), (8, - 1)

Solution

6

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, - 1)

and

(8, - 1)

is

= (8 - 2)^{2} + (- 1 - (- 1))^{2}

Simplify

= 6

Popular Examples

range of (3x-1)/(x+2)range

\frac{3 x - 1}{x + 2}

asymptotes of f(x)=(x-2)/(3x^2-36x-60)asymptotes

f (x) = \frac{x - 2}{3 x ^{2} - 36 x - 60}

critical x^2-5x+2 critical points

x^{2} - 5 x + 2

domain of f(x)=(2x^2-5)/(sqrt(x^2-x-6))domain

f (x) = \frac{2 x ^{2} - 5}{x ^{2} - x - 6}

domain of 16-0.9t domain

16 - 0.9 t

Frequently Asked Questions (FAQ)

What is the distance (2,-1),(8,-1) ?
The distance (2,-1),(8,-1) is 6