What is the domain of f(x)=(sqrt(7-x))/(x^2+1) ?

The domain of f(x)=(sqrt(7-x))/(x^2+1) is x<= 7

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domain of f(x)=(sqrt(7-x))/(x^2+1)

domain

f (x) = \frac{7 - x}{x ^{2} + 1}

x \leq 7

Interval Notation

(- \infty, 7]

Solution steps

Find non-negative values for radicals:

x \leq 7

The function domain

x \leq 7

- 2 x + 5 y = - 30

2 x^{3} - 12 x^{2} + 10 x + 10

\frac{x - 5}{8 x + 4}

\frac{1}{x ^{2} + 4}

2 - \frac{3}{x}

What is the domain of f(x)=(sqrt(7-x))/(x^2+1) ?
The domain of f(x)=(sqrt(7-x))/(x^2+1) is x<= 7