What is the intercepts of y=2x^2+x-1 ?

The intercepts of y=2x^2+x-1 is X Intercepts: (1/2 ,0),(-1,0),Y Intercepts: (0,-1)

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intercepts of y=2x^2+x-1

intercepts

y = 2 x^{2} + x - 1

X Intercepts : (\frac{1}{2}, 0), (- 1, 0), Y Intercepts : (0, - 1)

Solution steps

x -

axis interception points of

2 x^{2} + x - 1 : (\frac{1}{2}, 0), (- 1, 0)

y -

axis interception point of

2 x^{2} + x - 1 : (0, - 1)

X Intercepts : (\frac{1}{2}, 0), (- 1, 0), Y Intercepts : (0, - 1)

2 (x - 2)^{2} + 4

f (x) = - 2 x^{2} + 4

f (x) = - x^{4} + 4 x + 8

f (x) = \frac{- 3 x - 13 x}{x + 8}

ln (4 x^{4})

What is the intercepts of y=2x^2+x-1 ?
The intercepts of y=2x^2+x-1 is X Intercepts: (1/2 ,0),(-1,0),Y Intercepts: (0,-1)