What is the inverse of f(x)=((8x-1))/(2x+5) ?

The inverse of f(x)=((8x-1))/(2x+5) is (-1-5x)/(2(-4+x))

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inverse of f(x)=((8x-1))/(2x+5)

inverse

f (x) = \frac{( 8 x - 1 )}{2 x + 5}

\frac{- 1 - 5 x}{2 ( - 4 + x )}

Solution steps

y = \frac{8 x - 1}{2 x + 5}

Replace

x

with

y

x = \frac{8 y - 1}{2 y + 5}

Solve for

y, x = \frac{8 y - 1}{2 y + 5}

\frac{- 1 - 5 x}{2 ( - 4 + x )}

f (x) = \frac{2 x + 3}{1 - 5 x}

5 x - 3 y = - 15

f (x) = \frac{x - 3}{x - 5}

f (x) = 7^{x} + 4

x + sin (x)

What is the inverse of f(x)=((8x-1))/(2x+5) ?
The inverse of f(x)=((8x-1))/(2x+5) is (-1-5x)/(2(-4+x))